(3x^2-2x)/(5x-1)=0

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Solution for (3x^2-2x)/(5x-1)=0 equation: 


D( x )

5*x-1 = 0

5*x-1 = 0

5*x-1 = 0

5*x-1 = 0 // + 1

5*x = 1 // : 5

x = 1/5

x in (-oo:1/5) U (1/5:+oo)

(3*x^2-(2*x))/(5*x-1) = 0

(3*x^2-2*x)/(5*x-1) = 0

3*x^2-2*x = 0

x*(3*x-2) = 0

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

x*(x-2/3) = 0

(x*(x-2/3))/(5*x-1) = 0

( x-2/3 )

x-2/3 = 0 // + 2/3

x = 2/3

( x )

x = 0

x in { 2/3, 0 }

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